An electron moving with a velocity of 5× 104 ms-1 enters into a uniform electric field and acquires a uniform acceleration of 104 ms–2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this time?
Given initial velocity, u = 5 � 104 m/s
and acceleration, a = 104 m s�2
(i) final velocity = v = 2 u = 2 � 5 �10 4 m s�1
=10 � 104 m s�1
