###### MCQ Solution: Circles

If two equal circles of radius r passes through centre of the other then the length of their common chord is

1) r / Ö3

2) r Ö3

3) Ö3 r / 4

4) r Ö2

**SOLUTIONS **

**We know that, if two circles intersect each other, the line joining the centres in perpendicular bisector of common chord.**

**In D AOO'**

**Since all the sides are equal to ' r', therefore DAOO' is an equilateral triangle.**

**\ all angles are 60° **

**sin 60° = AM / AO**

**Ö3 /2 = AM / r **

** AM = Ö3 r/2 **

**AB = 2AM = Ö3 r/2 x 2 **

**= r Ö3 **

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