CBSE Notes, Lectures

CBSE - Physics - Motion

Motion

NCERT In Text

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h−1 in 10 minutes. Find its acceleration.

Initial velocity of the train, u= 0 (since the train is initially at rest)

Final velocity of the train, v= 40 km/h = 40 x 5/ 18 m/s = 11.11 m/s

Time taken, t = 10 min = 10 x 60 = 600 s



Hence, the acceleration of the train is 0.0185 m/s2.

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