CBSE Notes, Lectures

CBSE - Physics - Force and Laws of Motion

Force and Laws of Motion

NCERT Exercise

An object of mass 100 kg is accelerated uniformly from a velocity of 5 m s−1 to 8 ms−1 in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object.

Initial velocity of the object, u = 5 m/s
Final velocity of the object, v = 8 m/s
Mass of the object, m = 100 kg
Time take by the object to accelerate, t = 6 s
Initial momentum = mu = 100 × 5 = 500 kg m s−1
Final momentum = mv = 100 × 8 = 800 kg m s−1
Force exerted on the object, F = mv - mu / t
= m (v-u) / t
= 800 - 500
=  300 / 6
= 50 N

Initial momentum of the object is 500 kg m s−1.
Final momentum of the object is 800 kg m s.−1
Force exerted on the object is 50 N.

.