A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate
A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate
(i) the maximum height to which it rises.
(ii) the total time it takes to return to the surface of the earth.
Answer :
According to the equation of motion under gravity:
v2 - u2= 2 gs
Where,
u= Initial velocity of the ball
v= Final velocity of the ball
s= Height achieved by the ball
g= Acceleration due to gravity
At maximum height, final velocity of the ball is zero, i.e., v= 0
u = 49 m/s
During upward motion, g = - 9.8 m s- 2
Let h be the maximum height attained by the ball.
Hence,
Let t be the time taken by the ball to reach the height 122.5 m, then according
to the equation of motion:
v= u + gt
We get,
But,
Time of ascent = Time of descent
Therefore, total time taken by the ball to return = 5 + 5 = 10 s
(i) 122.5 m (ii) 10 s
