Compute the number of ions present in 5.85 g of sodium chloride.
5.85 g of NaCl 5.85 / 58.5 = 0.1 moles
Or 0.1 moles of NaCl particle
Each NaCl particle is equivalent to one Na+ one CI-
⇒ 2 ions
⇒Total moles of ions = 0.1 × 2
⇒2 moles
No. of ions = 0.2 × 6.022 × 1023
⇒1.2042 × 1023 ions
