B1, B2 and B3 are three identical bulbs connected as shown in Figure 12.8. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
B1, B2 and B3 are three identical bulbs connected as shown in Figure 12.8. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
(i) What happens to the glow of the other two bulbs when the bulb B1 gets fused?
Ans. In parallel circuit, potential difference does not get divided. Hence, glow of other bulbs will not be affected when bulb B1 gets fused.
(ii) What happens to the reading of A1, A2, A3 and A when the bulb B2 gets fused?
Ans. Ammeter A shows a reading of 3A. This means each of the A1, A2, and A3 show 1A reading.
When the bulb B2 gets fused, no current flows through this bulb. So, all the current is equally divided between remaining two bulbs. So, ammeters A1 and A2 will show 3/2 = 1.5 A current each. Ammeter A3 will show zero current.
(iii) How much power is dissipated in the circuit when all the three bulbs glow together?
Ans. For finding power, we need to first calculate the resistance in the circuit
