CBSE Notes, Lectures

CBSE - Physics - Electricity

Electricity

NCERT In Text

Judge the equivalent resistance when the following are connected in parallel − (a) 1 Ω and 106Ω, (b) 1 Ω and 103Ω and 106Ω.

(a) When 1 Ω and 106 Ω are connected in parallel:
Let R be the equivalent resistance.



Therefore, equivalent resistance ≈ 1 Ω

(b) When 1Ω, 103 Ω and 106 Ω are connected in parallel:

Let R be the equivalent resistance.



Therefore, equivalent resistance = 0.999 Ω

.