CBSE Notes, Lectures

CBSE - Physics - Electricity

Electricity

NCERT Exercise

When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.

Resistance (R) of a resistor is given by Ohm�s law as,V= IR
R= V/I
Where,
Potential difference, V= 12 V
Current in the circuit, I= 2.5 mA = 2.5 x 10-3 A



Therefore, the resistance of the resistor is 4.8 kΩ

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