In Fig. 7.49, ∠B < ∠A and ∠C < ∠D. Show that AD < BC.
Answer
Answer
Given,
∠B < ∠A and ∠C < ∠D
Now,
AO < BO --- (i) (Side opposite to the smaller angle is smaller)
OD < OC ---(ii) (Side opposite to the smaller angle is smaller)
Adding (i) and (ii)
AO + OD < BO + OC
⇒ AD < BC
