In the following figure, ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that (vi) ar(FED) = 1/8 ar(AFC)
In the following figure, ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that (vi) ar(FED) = 1/8 ar(AFC)
ANSWER:
(vi) Area (AFC) = area (AFD) + area (ADC)
