The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 g.
Given; R = 28 cm, r = 24 cm, h = 35 cm
Volume of pipe = π R2h – π r2h
= π h (R2 - r2)
= (22/7) X 35 (282 - 242)
= 110 (28 + 24)(28 – 24)
= 110 X 52 X 4 = 22880 cubic cm
Mass = 22880 X 0.6 g = 13728 g
