CBSE Notes, Lectures

CBSE - Mathematics - Arithematic Progressions

Arithematic Progressions

NCERT Exercise Exercise 5.2

Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P.
 

 

a

d

n

an

(i)

7

3

8

…...

(ii)

− 18

…..

10

0

(iii)

…..

− 3

18

− 5

(iv)

− 18.9

2.5

…..

3.6

(v)

3.5

0

105

…..

(i) a = 7, d = 3, n = 8, an = ?
We know that,
For an A.P. an = a + (n − 1) d
= 7 + (8 − 1) 3
= 7 + (7) 3
= 7 + 21 = 28
Hence, an = 28

(ii) Given that
a = −18, n = 10, an = 0, d = ?
We know that,
an = a + (n − 1) d
0 = − 18 + (10 − 1) d
18 = 9d
d = 18/9 = 2
Hence, common difference, = 2

(iii) Given that
= −3, n = 18, an = −5
We know that,
an = a + (n − 1) d
−5 = a + (18 − 1) (−3)
−5 = a + (17) (−3)
−5 = − 51
a = 51 − 5 = 46
Hence, a = 46

(iv) a = −18.9, d = 2.5, an = 3.6, n = ?
We know that,
an = a + (n − 1) d
3.6 = − 18.9 + (n − 1) 2.5
3.6 + 18.9 = (n − 1) 2.5
22.5 = (n − 1) 2.5
(n - 1) = 22.5/2.5
n - 1 = 9
n = 10
Hence, n = 10

(v) a = 3.5, d = 0, n = 105, an = ?
We know that,
an = a + (n − 1) d
an = 3.5 + (105 − 1) 0
an = 3.5 + 104 × 0
an = 3.5
Hence, an = 3.5

.