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CBSE - Mathematics - Arithematic Progressions

Arithematic Progressions

NCERT Exercise Exercise 5.3

 spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A of radii 0.5, 1.0 cm, 1.5 cm, 2.0 cm, ……… as shown in figure. What is the total length of such a spiral made up of thirteen consecutive semicircles? (Take π = 22/7)

perimeter of semi-circle = πr
P1 = π(0.5) = π/2 cm
P2 = π(1) = π cm
P3 = π(1.5) = 3π/2 cm
P1P2P3 are the lengths of the semi-circles

π/2, π, 3π/2, 2π, ....
P1 = π/2 cm
P2 = π cm
d = P2- P1 = π - π/2 = π/2
First term = P1 = a = π/2 cm
Sn = n/2 [2a + (n - 1)d]
Therefor, Sum of the length of 13 consecutive circles
S13 = 13/2 [2(π/2) + (13 - 1)π/2]
=  13/2 [π + 6π]
=13/2 (7π)  = 13/2 × 7 × 22/7
= 143 cm

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