CBSE Notes, Lectures

CBSE - Mathematics - Triangles

Triangles

NCERT Exercise Exercise 6.2

In figure.6.17. (i) and (ii), DE || BC. Find EC in (i) and AD in (ii)

(i) In ��� ABC, DE���BC (Given)

∴ AD/DB = AE/EC [By using Basic proportionality theorem]

⇒ 1.5/3 = 1/EC

⇒  EC = 3/1.5

EC = 3×10/15 = 2 cm
Hence, EC = 2 cm.

(ii) In ��� ABC, DE���BC (Given)
∴ AD/DB = AE/EC [By using Basic proportionality theorem]
⇒ AD/7.2 = 1.8/5.4
⇒ AD = 1.8×7.2/5.4 = 18/10 × 72/10 × 10/54 = 24/10
⇒ AD = 2.4
Hence, AD = 2.4 cm.

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