In the fig 6.18, if LM || CB and LN || CD, prove thatAM/MB = AN/AD
In the given figure, LM || CB
By using basic proportionality theorem, we get,
AM/MB = AL/LC ... (i)
Similarly, LN || CD
∴ AN/AD = AL/LC ... (ii)
From (i) and (ii), we get
AM/MB = AN/AD
