CBSE Notes, Lectures

CBSE - Mathematics - Triangles

Triangles

NCERT Exercise Exercise 6.3

In the fig 6.39, ABC and AMP are two right triangles, right angled at B and M respectively, prove that:


 

(i) ΔABC ~ ΔAMP

(ii) CA/PA = BC/MP

(i) In ΔABC and ΔAMP, we have

∠A = ∠A (common angle)

∠ABC = ∠AMP = 90° (each 90°)

∴  ΔABC ~ ΔAMP (By AA similarity criterion)

 

(ii) As, ΔABC ~ ΔAMP (By AA similarity criterion)

If two triangles are similar then the corresponding sides are equal,

Hence, CA/PA = BC/MP

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