ABC is an isosceles triangle with AC = BC. If AB2 = 2AC2, prove that ABC is a right triangle.
Given that ΔABC is an isosceles triangle having AC = BC and AB2 = 2AC2
In ΔACB,
AC = BC (Given)
AB2 = 2AC2 (Given)
AB2 = AC2 + AC2
= AC2 + BC2 [Since, AC = BC]
Hence, By Pythagoras theorem ΔABC is right angle triangle.
