CBSE Notes, Lectures

CBSE - Mathematics - Coordinate Geometry

Coordinate Geometry

NCERT Exercise Exercise 7.1

If Q (0, 1) is equidistant from P (5, - 3) and R (x, 6), find the values of x. Also find the distance QR and PR.

PQ = QR

41 = x2 + 25
16 = x2
x = ±4
Therefore, point R is (4, 6) or ( - 4, 6).
When point R is (4, 6),

.