In ΔABC right angled at B, AB = 24 cm, BC = 7 cm. Determine
(i) sin A, cos A
(ii) sin C, cos C
In Δ ABC,∠B = 90º
By Applying Pythagoras theorem , we get
AC2 = AB2 + BC2 = (24)2 + 72 = (576+49) cm2 = 625 cm2
⇒ AC = 25
(i) sin A = BC/AC = 7/25
cos A = AB/AC = 24/25
(ii) sin C = AB/AC = 24/25
cos C = BC/AC = 7/25
