CBSE Notes, Lectures

CBSE - Mathematics - Introduction to Trigonometry

Introduction to Trigonometry

NCERT Exercise Excercise 8.4

Choose the correct option. Justify your choice.
(i) 9 sec2A - 9 tan2A =
      (A) 1                 (B) 9              (C) 8                (D) 0
(ii) (1 + tan θ + sec θ) (1 + cot θ - cosec θ)
      (A) 0                 (B) 1              (C) 2                (D) - 1
(iii) (secA + tanA) (1 - sinA) =
      (A) secA           (B) sinA        (C) cosecA      (D) cosA

(iv) 1+tan2A/1+cot2A = 

      (A) sec2A                 (B) -1              (C) cot2A                (D) tan2A

(i) (B) is correct.

9 sec2A - 9 tan2A

= 9 (sec2A - tan2A)
= 9×1 = 9             (��� sec2 A - tan2 A = 1)


(ii) (C) is correct

(1 + tan θ + sec θ) (1 + cot θ - cosec θ)   

= (1 + sin θ/cos θ + 1/cos θ) (1 + cos θ/sin θ - 1/sin θ)

= (cos θ+sin θ+1)/cos θ × (sin θ+cos θ-1)/sin θ

= (cos θ+sin θ)2-12/(cos θ sin θ)

= (cos2θ + sin2θ + 2cos θ sin θ -1)/(cos θ sin θ)

= (1+ 2cos θ sin θ -1)/(cos θ sin θ)

= (2cos θ sin θ)/(cos θ sin θ) = 2


(iii) (D) is correct.

(secA + tanA) (1 - sinA)

= (1/cos A + sin A/cos A) (1 - sinA)

= (1+sin A/cos A) (1 - sinA)

= (1 - sin2A)/cos A

= cos2A/cos A = cos A


(iv) (D) is correct.

1+tan2A/1+cot2

= (1+1/cot2A)/1+cot2A

= (cot2A+1/cot2A)×(1/1+cot2A)

= 1/cot2A = tan2A

.