Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is 25 cm.
P= 1 / f (metres)
P = 1/ 0.33 m = + 3.0 D
A convex lens of power +3.0 D is required to correct the defect.