Solution :

At pressure P₁ = 1 bar,

        volume V₁ = 2.27 L 

At pressure P₂ = 0.2 bar,

      volume V₂ = to be calculated

As temperature remain constant at room temperature, applying Boyle’s law

                       P₁V₁ = P₂V₂

      (1 bar) (2.27 L) = (0.2 bar) V₂ 

Thus, the balloon can be expanded upto 11.35 L. Beyond this volume it will burst.