50 mL of each gas A and of gas B takes 200 and 150 s respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36, the molecular mass of gas A will be 1) 96 2) 128 3) 32 4) 64
50 mL of each gas A and of gas B takes 200 and 150 s respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36, the molecular mass of gas A will be
1) 96 2) 128 3) 32 4) 64
Solution :
From Graham’s law of effusion
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