CBSE Notes, Lectures
Menu
Account
Log Out
×
Dashboard
Courses
Videos
Test Series
CBSE
CBSE 12
CBSE 11
CBSE 10
CBSE 9
CBSE 8
TEST PREP
CUET
JEE
NDA
KVPY
INO-NSEP
INO-NSEC
NEET
NSEB
NTSE
NSEJS
Mentors
Books
Support
CBSE - Motion
Welcome, Students!
Eduinfy provide you digital online & effective learning for entrance exams .
Practice Question
Motion
.
Motion
The equations of motion can be derived by using:
(1) Distance– time graph
(2 Velocity – time graph for non-uniform acceleration
(3) Displacement time graph
(4) Velocity – time graph for uniform acceleration
Correct Answer: 4
.
Related Questions
Motion
1
The correct velocity-time graph for zero acceleration is:
(1) Graph-D
(2) Graph-A
(3) Graph-C
(4) Graph-B
Correct Answer: 4
2
The distance travelled by the body between 0 to 20 seconds?
(1) 260m
(2) 160m
(3) 300m
(4) 60m
Correct Answer: 3
3
The area under a velocity-time graph is represented by the unit:
(1) m
(2) m
-1
(3) m
3
(4) m
2
Correct Answer: 1
4
For a constant acceleration, the nature of velocity-time graph is:
(1) Graph-B
(2) Graph-D
(3) Graph-C
(4) Graph-A
Correct Answer: 4
5
A body of mass 2 kg is free to move along x-axis. It is at rest at t = 0. From t = 0 onwards it is subjected to a time dependent force F(t ) in x-direction. The variation of F with time is as shown :
The change in momentum during journey is (in N-s) :
(1) 4.50
(2) 7.50
(3) 5.06
(4) 14.06
Correct Answer: 1