MCQ Solution: Surface Chemistry
526.3 mL of 0.5 m HCl is shaken with 0.5 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 m. The amount of adsorption of HCl per unit mass of adsorbent is
1) 3
2) 6
3) 8
4) 4
Solution
Since the solution is dilute, molality can be approximated to molarity.
Due to adsorption, the molarity changes from 0.5 M to 0.4 M.
Hence, the number of moles of HCl adsorbed =(0.5−0.4)× (526.3 /1000) =0.05263 moles.
The mass of HCl adsorbed x =0.05263×36.5=1.9209 g
The mass of charcoal (m) is 0.5 g.
The amount of adsorption (x /m) = 1.9209 /0.5 ≈4
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