MCQ Solution: Electromagnetic Induction
An alternating voltage is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 volt and across the inductance is 150 volt, the applied voltage is
1) 350 volt
2) 250 volt
3) 500 volt
4) 300 volt
Solution
$$Total\quad PD\quad =\quad \sqrt { PD_{ Inductance }^{ 2 }+PD_{ resistance }^{ 2 } } \\$$
$$ PD\quad =\quad \sqrt { { 150 }^{ 2 }+{ 200 }^{ 2 } } $$
$$=250V$$
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