MCQ Solution: Chemical Kinetics
At a certain temperature, the first order rate constant k1 is found to be smaller than the second order rate constant k. If Ea(1) of the first order reaction is greater than Ea(2) of the second order reaction, then as temperature is raised :
1) k2 will increase faster than k1.
2) k1 will increase faster than k2 but will always remain less than k2.
3) k1 will increase faster than k2 and become equal to k2
4) k1 will increase faster than k2 and become greater than k2
Solution
As we know,
$$k = Ae^{-E_a/RT}$$
here,
as $$k_2 > k_1$$ so
$$k_2$$ will increase faster than $$k_1$$.