MCQ Solution: Electrochemistry
Calculate the standard free energy change for reaction,
2Ag + 2H+ → H2 + 2Ag+
E° for Ag+ + e- → Ag is 0.80V
1) +154.4 kJ
2) +308.8 kJ
3)-154.4 kJ
4)-308.8 kJ
SOLUTION
Given potential of Ag is reduction potential,
Hydrogen electrode is cathode(0Volt) and Ag is Anode(0.8Volt)
Cell potential = E cell=reduction potential of (cathode - Anode)
Cell potential E0 = 0-0.8 = -0.8Volts
ΔG=-nFe°
ΔG - -2 ×96500 ×(-0.80)=154.4kJ
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