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MCQ Solution: Ray Optics

The image of an object placed at 60cm in fromt of a lens is obtained on a screen at a distance of 120 cm from it. Find the local of the lens. what would be the height of the image if the object is 5cm high ?

1)  5cm
2) −10cm
3)  10cm
4) −20cm

 

 

 

 

 

 

Solution

Object distance u=−60 Image distance v=+120 cm Using lens formula,1/f=1/v−1/u

1/f=1/120−(−1/60)

= +40 cmH(image) / H(object) = v/u Hi

=−120/60X5
=−10v/uHi
=−120/60X5

=−10cm 

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