MCQ Solution: Solutions
The van't hoff factor for 0.1 molal Ba(NO3)2 solution is 2.74. Its degree of dissociation is
1) 0.74
2) 0.91
3) 0.87
4) 1.0
Solution
$$α =\frac{i−1}{(x+y)−1}$$
The van't hoff factor for 0.1 molal Ba(NO3)2 solution is 2.74. Its degree of dissociation is
1) 0.74
2) 0.91
3) 0.87
4) 1.0
$$α =\frac{i−1}{(x+y)−1}$$