MCQ Solution: Oscillations
The point of suspension of l simple pendulum with normal time period T1 is moving upward according to equation y = Kt2 where k = 1m/s2. If new time period is T2 the ratio T12 /T22 will be :
1) 2/3
2) 5/6
3) 6/5
4) 3/2
SOLUTION
We know that time period of pendulum of l length with net vertical acceleration anet is given by
Point of suspension moves acoording to y=Kt2
velocity of pt of susp v=dy / dt=2Kt
Acceleration of 10 t of susp
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