32. Fill in the missing data in the Table 3.1

(a) kilo
 (b) deci
(c) centi
 (d) micro
 (e) nano
 (f) pico

(a) 5.84 × 10^-3 mg
Ans. 5.84 × 10^-9 Kg

(b) 58.34 g
Ans. 5.834 ×10^-2 Kg

(c) 0.584 g
Ans. 
5.84 ×10^-4 Kg

(d) 5.873 × 10^-21 g
Ans. 5.873 × 10²⁴ Kg

A Mg²⁺ ion and Mg atom differ by two electrons.
 10³ moles of Mg²⁺ and Mg atoms would differ by
 10³×2 moles of electrons 
 Mass of 2×10³ moles of electrons = 2 x 10³ x 6.023 x 10²³ x 9.1 x 10 ^-31 kg

1.096 x 10^-3 Kg

NH₃  would have more atoms.

5.85 g of NaCl 5.85 / 58.5 = 0.1 moles 

Or 0.1 moles of NaCl particle
 Each NaCl particle is equivalent to one Na⁺ one CI^-

⇒ 2 ions 
⇒Total moles of ions = 0.1 × 2
⇒2 moles 
No. of ions  =  0.2 × 6.022 × 10²³
⇒1.2042 × 10²³ ions