NCERT Solution: Surface Areas and Volumes
Solution:
Volume of sphere = 4/3 π r3
= (4/3) X (22/7) X (4.2)3 = 310.464 cubic cm
Mass = volume X density
= 310.464 X 8.9
= 2763.1296 gm = 2.76 kg
Solution:
Volume of two similar shapes are in triplicate ratio of their dimensions. For example; if radii are R and r then ratio of volumes = R3 : r3
Hence, volume of earth/volume of moon
= 43 : 13
= 64 : 1
Solution:
Volume of hemisphere = 2/3 π r3
= (2/3) X (22/7) X (5.25)3 = 303.1875 cubic cm = 0.303 litre
Solution:
Inner radius r = 1 m, outer radius r = 1.01 m
Volume of metal = 4/3 π (R3 - r3)
= (4/3) X (22/7) [(1.01)3 - 13]
= (4/3) X (22/7) X 0.030301 = 0.06348 cubic m
Solution:
Surface area of sphere = 4 π r2
Or, 154 = 4 X (22/7) X r2
Or, r2 = (154 X 7)/(22 X 4) = 49/4
Or, r = 7/2 = 3.5 cm
Volume of sphere = 4/3 π r3
= (4/3) X (22/7) X (3.5)3 = 179.67 cubic cm
Solution:
Curved surface area of hemisphere = cost/rate
= 498.96/2 = 249.48 sq m
Or, 2 π r2 = 249.48
Or, r2 = (249.48 X 7)/(2 X 22)
Or, r = 6.3 m
Volume of hemisphere = 2/3 π r3
= (2/3) X (22/7) X (6.3)3 = 523.908 cubic m
Solution:
Here; ratio of volumes = 27 : 1
Radii shall be in sub-triplicate ratio, i.e. 3 : 1
Because 33 : 13 = 27 : 1
Now, surface areas shall be in duplicate ratio of radii
Hence, ratio of surface areas = 32 : 12 = 9 : 1
Solution:
Volume of sphere = 4/3 π r3
= (4/3) X (22/7) X (1.75)3
= 22.46 cubic mm