Polynomials
If the polynomial x3 + 2x2 - αx - 12 is divided by (x - 4) the remainder is 52. Find the value of
1) 11 / 2
2) - 5
3) 8
4) - 8
| A. | Option 1 |
| B. | Option 2 |
| C. | Option 3 |
| D. | Option 4 |
|
Option: 3 Solution : -. |
Polynomials
If α, β are the zeros of polynomial f(x) = x2 – p (x + 1) – c, then (α + 1) (β + 1) =
(a) c – 1
(b) 1 – c
(c) c
(d) 1 + c
| A. | Option 1 |
| B. | Option 2 |
| C. | Option 3 |
| D. | Option 4 |
|
Option: 2 Solution : -. |
Polynomials
If the polynomial x3 + 2x2 - αx - 12 is divided by (x - 4) the remainder is 52. Find the value of
1) 11 / 2
2) - 5
3) 8
4) - 8
| A. | Option 1 |
| B. | Option 2 |
| C. | Option 3 |
| D. | Option 4 |
|
Option: 3 Solution : -. |
Polynomials
If one of the zeroes of the quadratic polynomial (k-1)x2 + kx + 1 is -3,then the value of k is
1) -4/3
2) 4/3
3) 2/3
4) -2/3
| A. | Option 1 |
| B. | Option 2 |
| C. | Option 3 |
| D. | Option 4 |
|
Option: 2 Solution : -. |
Polynomials
If a and b are the zeros of the quadratic polynomial p(s) = 3s2 – 6s + 4, find the value of
is
1) 4
2) 8
3) 6
4) 3
| A. | Option 1 |
| B. | Option 2 |
| C. | Option 3 |
| D. | Option 4 |
|
Option: 2 Solution : -. |
Polynomials
The zeroes of the quadratic polynomial x2 + 99x + 127 are
1) both positive
2) both negative
3) both equal
4) one positive and one negative
| A. | Option 1 |
| B. | Option 2 |
| C. | Option 3 |
| D. | Option 4 |
|
Option: 2 Solution : -. |
Polynomials
p(x) = x4 -6x3 +16x2 -25x +10
q(x) = x2-2x+k
It is given
p(x) = r(x) q(x) + (x+a)
Find the value of k and a
1) 2,-2
2) 5 ,-5
3) 7,3
4) 3,-1
| A. | Option 1 |
| B. | Option 2 |
| C. | Option 3 |
| D. | Option 4 |
|
Option: 2 Solution : -. |
Polynomials
If one of the zeroes of the cubic polynomial ax3 + bx2 + cx + d is zero, the product of then other two zeroes is
1) -c/a
2) c/a
3) 0
4) -b/a
| A. | Option 1 |
| B. | Option 2 |
| C. | Option 3 |
| D. | Option 4 |
|
Option: 2 Solution : -. |
Polynomials
If a and b are the roots (zeros) of the polynomial f(x) = x2 – 3x + k such that α – β= 1, find the value of k.
1) 1
2) 4
3) 2
4) 5
| A. | Option 1 |
| B. | Option 2 |
| C. | Option 3 |
| D. | Option 4 |
|
Option: 3 Solution : -. |