Polynomials
Find the remainder when x4+x3-2x2+x+1 is divided by x-1
1) 1
2) 5
3) 2
4) 3
A. | Option 1 |
B. | Option 2 |
C. | Option 3 |
D. | Option 4 |
Option: 3 Solution : -. |
Polynomials
If one of the zeroes of the quadratic polynomial (k-1)x2 + kx + 1 is -3,then the value of k is
1) -4/3
2) 4/3
3) 2/3
4) -2/3
A. | Option 1 |
B. | Option 2 |
C. | Option 3 |
D. | Option 4 |
Option: 2 Solution : -. |
Polynomials
If α and β are the zeroes of the polynomial f(x) = x2 – 5x + k such that α – β = 1, then value of k is:
(1) 8
(2) 6
(3) 13 / 2
(4) 4
A. | Option 1 |
B. | Option 2 |
C. | Option 3 |
D. | Option 4 |
Option: 2 Solution : -. |
Polynomials
On dividing f(x) = x3 – 3x2 + x + 2 by a polynomial g(x), the quotient and remainder were x – 2 and – 2x + 4, respectively. Find g(x)..
1) x2 – x + 1
2) x2 + x + 1
3) x2 – x – 1
4) x3 – x2 + x + 1
A. | Option 1 |
B. | Option 2 |
C. | Option 3 |
D. | Option 4 |
Option: 1 Solution : -. |
Polynomials
p(x) = x4 -6x3 +16x2 -25x +10
q(x) = x2-2x+k
It is given
p(x) = r(x) q(x) + (x+a)
Find the value of k and a
1) 2,-2
2) 5 ,-5
3) 7,3
4) 3,-1
A. | Option 1 |
B. | Option 2 |
C. | Option 3 |
D. | Option 4 |
Option: 2 Solution : -. |
Polynomials
If a and b are the zeros of the quadratic polynomial p(s) = 3s2 – 6s + 4, find the value of
is
1) 4
2) 8
3) 6
4) 3
A. | Option 1 |
B. | Option 2 |
C. | Option 3 |
D. | Option 4 |
Option: 2 Solution : -. |
Polynomials
If α, β are the zeros of polynomial f(x) = x2 – p (x + 1) – c, then (α + 1) (β + 1) =
(a) c – 1
(b) 1 – c
(c) c
(d) 1 + c
A. | Option 1 |
B. | Option 2 |
C. | Option 3 |
D. | Option 4 |
Option: 2 Solution : -. |
Polynomials
If zeroes of the quadratic polynomial x2+(a+1)x+b are 2 and -3 then find the value of a and b
1) 0, 6
2) 1, -6
3) 0, -6
4) -6, 0
A. | Option 1 |
B. | Option 2 |
C. | Option 3 |
D. | Option 4 |
Option: 3 Solution : -. |
Polynomials
If the polynomial x3 + 2x2 - αx - 12 is divided by (x - 4) the remainder is 52. Find the value of
1) 11 / 2
2) - 5
3) 8
4) - 8
A. | Option 1 |
B. | Option 2 |
C. | Option 3 |
D. | Option 4 |
Option: 3 Solution : -. |